(x^2+2)+(x^2+2)=16

Solution for (x^2+2)+(x^2+2)=16 equation:

Simplifying
(x2 + 2) + (x2 + 2) = 16

Reorder the terms:
(2 + x2) + (x2 + 2) = 16

Remove parenthesis around (2 + x2)
2 + x2 + (x2 + 2) = 16

Reorder the terms:
2 + x2 + (2 + x2) = 16

Remove parenthesis around (2 + x2)
2 + x2 + 2 + x2 = 16

Reorder the terms:
2 + 2 + x2 + x2 = 16

Combine like terms: 2 + 2 = 4
4 + x2 + x2 = 16

Combine like terms: x2 + x2 = 2x2
4 + 2x2 = 16

Solving
4 + 2x2 = 16

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 2x2 = 16 + -4

Combine like terms: 4 + -4 = 0
0 + 2x2 = 16 + -4
2x2 = 16 + -4

Combine like terms: 16 + -4 = 12
2x2 = 12

Divide each side by '2'.
x2 = 6

Simplifying
x2 = 6

Take the square root of each side:
x = {-2.449489743, 2.449489743}